Topic: Electrochemistry, Test No.: 05, Total MCQs: 10
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Question 1 |
Among the following cells
Leclanche cell (I), Nickel-cadmium cell (II), Lead storage battery (III), Mercury cell (IV)
Primary cells areI and II | |
I and III | |
II and III | |
I and IV |
Question 2 |
An
infinite dilution of aqueous solution of BaCl2, molar conductivity
of Ba2+ and Cl- ions are = 127.32 S cm2/mol
and 76.34 S cm2/mol respectively. What is for BaCl2
at same dilute?
280 S cm2
mol-1 | |
330.98 S
cm2 mol-1 | |
90.98 S
cm2 mol-1 | |
203.6 S
cm2 mol-1 |
Question 3 |
Aqueous
copper sulphate solution is electrolyzed using platinum electrodes. The
electrode reaction occurring at cathode is
Cu2+
(aq) + 2e– →
Cu(s) | |
Cu(s) → Cu2+ (aq) + 2e– | |
2H2O(l)
→ O2(g) +
4H+ (aq) + 4e– | |
O2(g)
+ 4H+ (aq) + 4e– →
2H2O(l) |
Question 4 |
Calculate the reduction potential of a half-cell containing platinum electrode immersed in 2.0 M Fe2+ and 0.02 M Fe3+.
Given = 0.771 V.
Fe3+ + e- → Fe2+
0.653 V | |
0.889 V | |
0.683 V | |
2.771 V |
Question 5 |
Conductivity of 0.01 M NaCl solution is 0.00147 ohm–1 cm–1. What happens to this conductivity if extra 100 ml of H2O will be added to the above solution?
Increases | |
Decreases | |
Remains unchanged | |
First increases and then decreases |
Question 6 |
Consider the following four electrodes,
P = Cu2+ (0.0001 M) | Cu(s)
Q = Cu2+ (0.1 M) | Cu(s)
R = Cu2+ (0.01 M) | Cu(s)
S = Cu2+ (0.001 M) | Cu(s)
If the standard reduction potential of Cu2+/Cu is +0.34 V, the reduction potentials in volts of the above electrodes follow the order
P > S > R > Q | |
S > R > Q > P | |
R > S > Q > P | |
P > Q > R > S |
Question 7 |
Cr2O72– + I– → I2 + Cr3+
EѲcell = 0.79 V and EѲCr2O72– = 133 V. EѲ I2 is
0.54 V | |
– 0.54 V | |
+ 0.18 V | |
– 0.18 V |
Question 8 |
Faraday’s constant is defined as
charge carried by 1 electron | |
charge carried by one mole of electrons | |
charge required to deposit one mole of a substance | |
charge carried by two moles of electrons |
Question 9 |
How many moles of Pt may be deposited on the cathode when 0.80 F of electricity is passed through a 1.0 M solution of Pt4+?
1.0 mol | |
0.20 mol | |
0.40 mol | |
0.80 mol |
Question 10 |
Molar ionic conductivities of a bivalent electrolyte are 57 and 73. The molar conductivity of the solution will be
130 S cm2
mol-1 | |
65 S cm2
mol-1 | |
260 S cm2
mol-1 | |
187 S cm2
mol-1 |
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