Oscillation Questions: Paper - 04 |
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1. |
The period of simple pendulum is doubled when (CPMT 74) (a) Its length is doubled (b) Its length is halved (c) The length is made four times (d) Mass of the bob is doubled
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2. |
If the length of a simple pendulum is doubled keeping its amplitude constant its energy will be (MHT CET 2001) (a) Unchanged (b) Doubled (c) Four times (d) Halved
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3. |
If an simple pendulum oscillates with an amplitude of 50 mm and time period of 2s, then its maximum velocity is (MHT-CET-2000) (a) 0.10 m/s (b) 0.16 m/s (c) 0.25 m/s (d) 0.5 m/s
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4. |
Starting from the extreme position, the time taken by an ideal simple pendulum to travel a distance of half of the amplitude is (MHT-CET-2007) (a) T/6 (b) T/12 (c) T/13 (d) T/4
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5. |
If a simple harmonic oscillator has got a displacement of 0.02 m and acceleration equal to 2.0 ms-2 at any time, the angular frequency of the oscillator is equal to (CBSE 92) (a) 10 rad s-1 (b) 0.1 rad s-1 (c) 100 rad s-1 (d) 1 rad s-1
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6. |
A body is executing S.H.M. when the displacements from the mean position are 4 cm and 5 cm, the corresponding velocities of the body are 10 cm/s and 8 cm/s respectively. The time period of oscillation is (MHT CET 2001, CBSE 91) (a) 5 second (b) 3.14 second (c) 2 second (d) 6.28 second
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7. |
The period of thin magnet is 4 sec. if it is divided into two equal halves then the time period of each part will be (MHT CET 2004) (a) 4 sec (b) 1 sec (c) 2 sec (d) 8 sec
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8. |
The force constant of a wire is K and that of another wire of the same material is 2K. when both the wires are stretched, then work done is (MHT-CET-2000) (a) W2 = 0.5 W1 (b) W2 = W1 (c) W2 = 2W2 (d) W2 = 2W12
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9. |
The acceleration due to gravity changes from 9.8 m/s2 to 9.5 m/s2. To keep the period of pendulum constant, its length must changes by (MHT-CET-2006) (a) 3 m (b) 0.3 m (c) 0.3 cm (d) 3 cm
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10. |
A simple
harmonic oscillator has an amplitude a and time period T. the time required
to travel from x = (a) (c)
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11. |
Two springs of constants k1 and k2 equal maximum velocities, when executing simple harmonic motion. The ratio of their amplitudes (masses are equal) will be (MHT-CET-2000) (a) (c)
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12. |
A load of mass 100 gm increases the length of wire by 10 cm. If the system is kept in oscillation, its time period is (MHT-CET-2006) (a) 0.314 s (b) 3.14 s (c) 0.628 s (d) 6.28 s
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13. |
A spring has a force constant K and a mass m is suspended from it. The spring is cut into half and the same a mss is suspended from one of the halves. If the frequency of oscillation in the first case is a, then the frequency in the second case will be (CPMT 86) (a) 2 a (b) a (c)
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14. |
A particle executes S.H.M. with amplitude 0.5 cm and frequency 100 Hz. The maximum speed of particle will be (CPMT 84) (a) p m/s (b) 5 p ´ 10-5 m/s (c) 0.5 m/s (d) 100 p m/s
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15. |
A particle executes simple pendulum harmonic motion of amplitude A. at what distance from the mean position is its kinetic energy to its potential energy? (MHT-CET-1999) (a) 0.51 A (b) 0.61 A (c) 0.71 A (d) 0.81 A |
16. |
A particle of mass m is executing SHM about its mean position. The total energy of the particle at given instant is (a) (c)
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17. |
Two bodies M and N of equal masses are suspended from two separate mass less springs of spring constants k1 and k2 respectively. If the two bodies oscillate vertically such that their maximum velocities are equal, the ratio of the amplitudes of M to that of N is (IIT 88) (a) (c)
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18. |
A simple harmonic motion having an amplitude A and time period T is represented by the equation y = 5 sin p (t + 4)m then the values of (A in m) and (T in sec) are (MNR 91) (a) A = 5, T = 2 (b) A = 10, T = 1 (c) A = 5, T = 1 (d) A = 10, T = 2
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19. |
If the length of simple pendulum is increased by 44% then what is the change in the time period of the pendulum? (MHT-CET 2004) (a) 22 % (b) 20 % (c) 33 % (d) 44 %
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20. |
The maximum velocity and maximum acceleration of a body moving in a simple harmonic oscillator are 2m/s and 4m/s2 the angular velocity is (MHT-CET-1999) (a) 1 rad/s (b) 2 rad/s (c) 4 rad/s (d) 5 rad/s
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21. |
If a bar magnet of magnetic moment M is kept in a uniform magnetic field B, its time period of oscillation is T. The another magnet of same length and breadth is kept in a same magnetic field. If magnetic moment of new magnet is M/4, then its oscillation time period is (MHT-CET-2006) (a) T (b) 2T (c) T/2 (d) T/4
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22. |
For a particle executing simple harmonic motion, the kinetic energy K is given by K = K0 cos2 wt. the maximum value of potential energy is (CPMT 81) (a) K0 (b) Zero (c)
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23. |
A body of mass 5 gm is moving at the centre with amplitude of 10 cm. its maximum velocity is 100 cm/s. its velocity will be 50 cm/s at a distance (in cm) (CPMT 76) (a) (c) 10 (d)
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24. |
The unit of force constant is (MHT-CET 99) (a) Nm (b) N/m (c) N/kg (d) Nkg
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25. |
The maximum velocity of a body in S.H.M. is 0.25 m/s and maximum acceleration is 0.75 m/s2, the period of S.H.M. is (a) (c) |
| Answers to Oscillation, Paper 4 (Go to top) | |
1. Answer: (c) 2. Answer: (d) 3. Answer: (b) 4. Answer: (a) 5. Answer: (a) 6. Answer: (b) 7. Answer: (c) 8. Answer: (c) 9. Answer: (d) 10. Answer: (a) 11. Answer: (d) 12. Answer: (c) 13. Answer: (d) 14. Answer: (a) 15. Answer: (c) 16. Answer: (b) 17. Answer: (d) 18. Answer: (a) 19. Answer: (b) 20. Answer: (b) 21. Answer: (b) 22. Answer: (a) 23. Answer: (b) 24. Answer: (b) 25. Answer: (c) |
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) 
is (CBSE
92)
(b) 
(d) 
(b) 
(d) 
(d) 
(b) 
(d) 
(d) Not
obtainable
(b) 
second (b) 
second
second (d)